(25x^(1/2)+x-13^2-7)

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Solution for (25x^(1/2)+x-13^2-7) equation: 


D( x )

x < 0

x < 0

x in <0:+oo)

x+25*x^(1/2)-13^2-7 = 0

x+25*x^(1/2)-176 = 0

t_1 = x^(1/2)

1*t_1^2+25*t_1^1-176 = 0

t_1^2+25*t_1-176 = 0

DELTA = 25^2-(-176*1*4)

DELTA = 1329

DELTA > 0

t_1 = (1329^(1/2)-25)/(1*2) or t_1 = (-1329^(1/2)-25)/(1*2)

t_1 = (1329^(1/2)-25)/2 or t_1 = (-(1329^(1/2)+25))/2

t_1 = (-(1329^(1/2)+25))/2

x^(1/2)-((-(1329^(1/2)+25))/2) = 0

x^(1/2)+(1/2)*(1329^(1/2)+25) = 0

1*x^(1/2) = -(1/2*(1329^(1/2)+25)) // : 1

x^(1/2) = -1/2*(1329^(1/2)+25)

( -1/2*(1329^(1/2)+25) < 0 i 1/2 in (0:1) ) => x naleu017Cy do O

t_1 = (1329^(1/2)-25)/2

x^(1/2)-((1329^(1/2)-25)/2) = 0

1*x^(1/2) = (1329^(1/2)-25)/2 // : 1

x^(1/2) = (1329^(1/2)-25)/2

x^(1/2) = (1329^(1/2)-25)/2 // ^ 2

x = ((1329^(1/2)-25)^2)/4

x = ((1329^(1/2)-25)^2)/4

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